Kid Einsteins · Distributive Property · Grades 3–5 · NYC Math Class
Distributive Thinking & Partial Products — 25 Practice Questions with Theory & Hidden Answers (Kid Einsteins)
The single most useful idea in grade-school multiplication: split a hard problem into two easier ones. This class-ready lesson teaches the distributive property and partial products using area models and the box method, then finishes with 25 practice questions — 10 easy, 10 medium, 5 hard — each with click-to-reveal step-by-step answers. Built for the SOMATH Kid Einsteins program (grades 3–5) on the Upper West Side of Manhattan.
This is Class 4 of the SOMATH Kid Einsteins multiplication arc. In Class 3 we drilled the three trickiest times tables (×7, ×8, ×9) using the area model. In this class we take the same picture — a rectangle chopped in two — and turn it into the engine for every hard multiplication your student will ever meet: multi-digit numbers, algebraic expressions, even fractions.
The main idea is only one sentence: if a multiplication is too hard to see in one step, split one of the numbers into two friendlier pieces, multiply each piece, and add. That’s distributive thinking. The two smaller multiplications you get are called partial products. This lesson makes both ideas concrete, then drills them with 25 questions. Written by the same team that teaches Kid Einsteins at SOMATH, run by cofounders Marcelo Ambrozio (Northwestern) and Vivianne Wright (Harvard).
- Warm-up: read the theory aloud and draw one split rectangle together (10 min).
- Work through the box-method example 23 × 47 as a class (10 min).
- Students attempt the 25 questions with the answers hidden (20 min).
- Reveal answers together and re-teach any that missed 3+ students (10 min).
What’s in this lesson
- The one-sentence big idea
- Theory: what the distributive property really says
- Theory: partial products (splitting by place value)
- The box method — the area model as a table
- Two-digit × two-digit with the box method
- How this becomes the standard algorithm
- Six friendly splits every student should know
- 25 practice questions (10 easy, 10 medium, 5 hard)
- Answer key summary
- About SOMATH & Kid Einsteins
1. The one-sentence big idea
Every technique in this class — area models, partial products, the box method, and the standard algorithm — is the same idea in different clothing. Once a student sees that a multiplication is a rectangle that can be chopped in two, hard multiplication becomes almost automatic.
2. Theory: what the distributive property really says
Split the sum, then add the pieces
The distributive property says that multiplying a number by a sum is the same as multiplying by each piece of the sum and adding the results:
a × (b + c) = (a × b) + (a × c)In everyday language: “multiply, then add” equals “add, then multiply.” As a picture, it’s a rectangle sliced into two smaller rectangles.
Example: 6 × 13. The number 13 is not on any times table you memorized — but 13 = 10 + 3, and both of those are easy:
6 × 13 = 6 × (10 + 3) = (6 × 10) + (6 × 3) = 60 + 18 = 78| × | 10 | 3 |
| 6 | 60 | 18 |
Split 13 into 10 + 3. Green box: 6 × 10 = 60. Gold box: 6 × 3 = 18. Add: 60 + 18 = 78.
The magic is not the property — it’s the freedom. You get to pick the split. Always pick the split that lands you on numbers you already know.
3. Theory: partial products (splitting by place value)
The place-value split is the one to memorize
A partial product is one of the smaller multiplications you get after splitting. The most useful split is always by place value: break a two-digit number into its tens and its ones.
Example: 27 × 4. Split 27 into 20 + 7:
27 × 4 = (20 × 4) + (7 × 4) = 80 + 28 = 108| × | 20 | 7 |
| 4 | 80 | 28 |
Two partial products: 80 and 28. Add them to get 108.
Why place value? Because multiplying by 10, 20, 30, 100, 200, and so on is just a smaller multiplication followed by adding zeros. So splitting by tens and ones guarantees that at least one of your partial products is easy.
- 20 × 4 = 2 × 4 × 10 = 80
- 30 × 6 = 3 × 6 × 10 = 180
- 40 × 50 = 4 × 5 × 100 = 2000
4. The box method — the area model as a table
Rows, columns, and one cell per partial product
The box method is the area-model rectangle written as a grid. Break the factors into place-value pieces along the top and left of a table. Fill in each cell with that row’s piece times that column’s piece. Add all the cells.
Example: 46 × 7. Split 46 into 40 + 6. One row, two columns:
| × | 40 | 6 |
| 7 | 280 | 42 |
Two partial products: 7 × 40 = 280 and 7 × 6 = 42. Total: 280 + 42 = 322.
The box method has two virtues: it never hides a step, and it works with any size number. You can split into three pieces, four pieces, hundreds and tens and ones. Same picture every time.
5. Two-digit × two-digit with the box method
Two-by-two grid, four partial products
When both factors are two-digit numbers, split both of them. You get a two-by-two box with four partial products.
Example: 23 × 47. Split: 23 = 20 + 3 and 47 = 40 + 7.
| × | 40 | 7 |
| 20 | 800 | 140 |
| 3 | 120 | 21 |
Four partial products, one per cell. Add all four to get the answer.
Notice: every partial product is a fact you already know. 2 × 4 = 8 makes 20 × 40 = 800. 3 × 7 = 21 stays 21. The box method is nothing more than four small multiplications plus one addition.
6. How this becomes the standard algorithm
The stacked algorithm is compressed partial products
When you learn to stack numbers and “carry the 1” in 4th or 5th grade, you are doing the same partial products — just compressed. Every line of the stacked algorithm is a partial product.
Example: 23 × 47 the stacked way (this reads bottom-up, right-to-left):
23 × 47 ______ 161 ← 23 × 7 = (20 × 7) + (3 × 7) = 140 + 21 = 161 + 920 ← 23 × 40 = (20 × 40) + (3 × 40) = 800 + 120 = 920 ______ 1,081Two lines instead of four cells — but the same four partial products are living inside those two lines. The box method makes them visible; the algorithm hides them for speed. Both are correct. Teach the box first, then the algorithm makes sense.
7. Six friendly splits every student should know
Pick the split so the pieces are easy
- Times 11: Split into 10 + 1. 7 × 11 = 70 + 7 = 77.
- Times 12: Split into 10 + 2. 6 × 12 = 60 + 12 = 72.
- Times 15: Split into 10 + 5. 8 × 15 = 80 + 40 = 120.
- Times 19: Split into 20 − 1 (subtract instead of add). 6 × 19 = 120 − 6 = 114.
- Times 25: Split into 20 + 5 or think “a quarter of 100.” 8 × 25 = 160 + 40 = 200.
- Times 99: Split into 100 − 1. 7 × 99 = 700 − 7 = 693.
The general rule: split so that one piece is a multiple of 10 (or 100). Multiplying by 10 or 100 is free — the rest is just an easier fact.
25 Practice Questions
10 easy, 10 medium, 5 hard. Every question can be solved with a split of your choosing — try to pick the friendliest split each time. Click Show answer & solution to check your reasoning.
Question 1 Easy
Use the split 14 = 10 + 4 to compute 3 × 14.
Answer: 42
3 × 14 = 3 × (10 + 4) = (3 × 10) + (3 × 4) = 30 + 12 = 42Two partial products: 30 and 12. Splitting by place value turns a “3 × 14” step into two facts your student already knows.
Question 2 Easy
Use the split 16 = 10 + 6 to compute 5 × 16.
Answer: 80
5 × 16 = (5 × 10) + (5 × 6) = 50 + 30 = 80Partial products 50 and 30. Notice both are multiples of ten — sometimes the split gives you two very tidy pieces.
Question 3 Easy
Ms. Chen buys 6 packs of markers. Each pack has 12 markers. How many markers does she have in total?
Answer: 72 markers
6 × 12 = (6 × 10) + (6 × 2) = 60 + 12 = 72Split 12 into 10 + 2. Two partial products (60 and 12), quick addition, done.
Question 4 Easy
A minivan holds 7 people. A tour company runs 13 minivans. How many people can ride in total?
Answer: 91 people
7 × 13 = (7 × 10) + (7 × 3) = 70 + 21 = 91Split 13 into 10 + 3. The two partial products are 70 and 21; add them to get 91.
Question 5 Easy
Use place-value splitting to compute 8 × 15. Show the two partial products.
Answer: 120
8 × 15 = (8 × 10) + (8 × 5) = 80 + 40 = 120Partial products 80 and 40. Both are multiples of 10 — that’s the friendly split of 15 doing its job.
Question 6 Easy
A rectangular garden is 4 feet wide and 18 feet long. What is its area?
Answer: 72 square feet
4 × 18 = (4 × 10) + (4 × 8) = 40 + 32 = 72Area is length × width. Split 18 into 10 + 8. The two partial products (40 and 32) are literally the two smaller rectangles the garden splits into.
Question 7 Easy
Use the split 19 = 20 − 1 to compute 6 × 19.
Answer: 114
6 × 19 = (6 × 20) − (6 × 1) = 120 − 6 = 114Splits can subtract too. Because 19 is one less than 20, it’s often easier to overshoot to 20 and take one copy back.
Question 8 Easy
A pack of stickers has 25 stickers. Ana buys 4 packs. How many stickers does she have?
Answer: 100 stickers
4 × 25 = (4 × 20) + (4 × 5) = 80 + 20 = 100Split 25 into 20 + 5. Partial products 80 and 20. Nice round total — that’s the ×25 pattern (4 groups of 25 = 100 = a full dollar).
Question 9 Easy
A carton holds 6 eggs. A store receives 17 cartons. How many eggs is that in total?
Answer: 102 eggs
6 × 17 = (6 × 10) + (6 × 7) = 60 + 42 = 102Split 17 into 10 + 7. Both partial products (60 and 42) are facts your student already knows from earlier Kid Einsteins classes.
Question 10 Easy
Draw the box method for 5 × 24. What are the two partial products, and what is the answer?
Answer: partial products 100 and 20; total 120
| × | 20 | 4 |
| 5 | 100 | 20 |
Two cells, two partial products. This box is the same picture as a 5-by-24 rectangle cut into a 5-by-20 piece and a 5-by-4 piece.
Question 11 Medium
Compute 23 × 6 using partial products.
Answer: 138
23 × 6 = (20 × 6) + (3 × 6) = 120 + 18 = 138Two partial products: 120 and 18. This is exactly what a 5th grader is doing in their head when they “multiply, carry the 1.”
Question 12 Medium
A school orders 36 pizzas, and each pizza is cut into 8 slices. How many slices are there in total?
Answer: 288 slices
8 × 36 = (8 × 30) + (8 × 6) = 240 + 48 = 288Split 36 into 30 + 6. Partial products 240 and 48.
Question 13 Medium
Marcus reads 27 pages per day for 7 days. How many pages does he read in the week?
Answer: 189 pages
7 × 27 = (7 × 20) + (7 × 7) = 140 + 49 = 189Split 27 into 20 + 7. Notice that 7 × 7 = 49 is one of the trickier facts from Class 3 — that’s why we drilled it.
Question 14 Medium
A theater has 14 rows and 15 seats in each row. How many seats does the theater have?
Answer: 210 seats
| × | 10 | 5 |
| 10 | 100 | 50 |
| 4 | 40 | 20 |
Two-digit × two-digit means four partial products. This is our first taste of the 2×2 box — the same picture we’ll use for 23 × 47.
Question 15 Medium
Compute 45 × 12 using the box method.
Answer: 540
| × | 40 | 5 |
| 10 | 400 | 50 |
| 2 | 80 | 10 |
Four partial products: 400, 50, 80, 10. Notice how quickly they add when you group the round ones first: 400 + 80 = 480, then 50 + 10 = 60, then 480 + 60 = 540.
Question 16 Medium
A gym class has 25 students in each of 8 sections. How many students are in gym class in total?
Answer: 200 students
8 × 25 = (8 × 20) + (8 × 5) = 160 + 40 = 200Split 25 into 20 + 5. Alternate shortcut: 4 groups of 25 make 100, so 8 groups make 200. Both routes give the same answer — that’s the point of distributive thinking.
Question 17 Medium
Use the split 99 = 100 − 1 to compute 7 × 99.
Answer: 693
7 × 99 = (7 × 100) − (7 × 1) = 700 − 7 = 693Multiplying by 99 looks scary but is really “multiply by 100, then subtract one copy.” The distributive property works with subtraction too: a × (b − c) = (a × b) − (a × c).
Question 18 Medium
A parking garage has 18 floors, and each floor holds 24 cars. How many cars can the garage hold?
Answer: 432 cars
| × | 20 | 4 |
| 10 | 200 | 40 |
| 8 | 160 | 32 |
Four partial products: 200, 40, 160, 32. Grouped adds: 200 + 160 = 360, then 40 + 32 = 72, then 360 + 72 = 432.
Question 19 Medium
Which is bigger, 6 × 47 or 7 × 39? Use partial products to compare.
Answer: 6 × 47 is bigger (282 vs. 273, a difference of 9)
6 × 47 = (6 × 40) + (6 × 7) = 240 + 42 = 282 7 × 39 = (7 × 40) − (7 × 1) ← split 39 as 40 − 1 = 280 − 7 = 273Two different products, both handled by splitting into a friendly form. Then compare: 282 > 273 by 9.
Question 20 Medium
A soccer league has 16 teams. Each team has 23 players. How many players are in the league?
Answer: 368 players
| × | 20 | 3 |
| 10 | 200 | 30 |
| 6 | 120 | 18 |
Four partial products, all small. Grouped adds: 200 + 120 = 320, then 30 + 18 = 48, then 320 + 48 = 368.
Question 21 Hard
Compute 23 × 47 using the box method. Show the four partial products.
Answer: 1,081
| × | 40 | 7 |
| 20 | 800 | 140 |
| 3 | 120 | 21 |
Four partial products: 800, 140, 120, 21. Add them any order you like. This is the “canonical” two-digit × two-digit example — every student should be able to write this grid from memory by the end of Class 4.
Question 22 Hard
A school buys 36 boxes of notebooks. Each box holds 48 notebooks. How many notebooks did the school buy?
Answer: 1,728 notebooks
| × | 40 | 8 |
| 30 | 1,200 | 240 |
| 6 | 240 | 48 |
Four partial products, two of which happen to be equal (240 appears twice). Grouped adds: 1,200 + 240 + 240 = 1,680, then 1,680 + 48 = 1,728.
Question 23 Hard
Fill in the missing partial product so that 28 × 15 = 200 + \_\_\_ + 80 + 40. What is the missing partial product, and what is the total?
Answer: missing partial product = 100; total = 420
28 × 15 = (20 × 10) + (20 × 5) + (8 × 10) + (8 × 5) = 200 + 100 + 80 + 40 = 420| × | 10 | 5 |
| 20 | 200 | 100 |
| 8 | 80 | 40 |
The missing cell is 20 × 5 = 100. This kind of “find the missing partial product” problem is the fastest way to check that a student really understands the box method — not just how to fill it in, but how to read it.
Question 24 Hard
A rectangular auditorium is being tiled. The floor is 34 feet by 26 feet. Each tile is exactly 1 square foot. How many tiles are needed? Use the box method and list your four partial products.
Answer: 884 tiles
| × | 20 | 6 |
| 30 | 600 | 180 |
| 4 | 80 | 24 |
Area of the auditorium in square feet is the same as the number of 1-by-1 tiles. Four partial products: 600, 180, 80, 24. The box method is literally how a contractor would break up the floor to tile it in sections.
Question 25 Hard
Challenge: A gardener has a rectangular plot that is 25 feet by 18 feet. She adds a 2-foot-wide walking path along the entire 25-foot side, making the plot 25 feet by 20 feet. What is the area of the new plot, and what is the area of just the path? Use distributive thinking.
Answer: new plot area = 500 sq ft; path area = 50 sq ft
Original plot: 25 × 18 = (25 × 10) + (25 × 8) = 250 + 200 = 450 sq ft New plot: 25 × 20 = 500 sq ft (a friendly multiple of 100) Path area = new − original = 500 − 450 = 50 sq ft Or directly: 25 × 2 = 50 sq ft ← the path IS a 25-by-2 rectangleTwo ways to see the same answer. Distributively: 25 × 20 = 25 × (18 + 2) = (25 × 18) + (25 × 2) = 450 + 50 = 500. That last line is the whole idea of this lesson in one equation: adding a piece to a rectangle’s side is exactly the same as adding a new rectangle of partial products. This is also the picture your student will use again when they FOIL (x + 2)(x + 5) in Algebra 1 — same rectangle, same split, same answer.
Answer key summary
| Q# | Answer | Q# | Answer | Q# | Answer |
|---|---|---|---|---|---|
| 1 | 42 | 10 | 120 | 19 | 6×47 (282) |
| 2 | 80 | 11 | 138 | 20 | 368 |
| 3 | 72 | 12 | 288 | 21 | 1,081 |
| 4 | 91 | 13 | 189 | 22 | 1,728 |
| 5 | 120 | 14 | 210 | 23 | 100; total 420 |
| 6 | 72 | 15 | 540 | 24 | 884 |
| 7 | 114 | 16 | 200 | 25 | 500 & 50 |
| 8 | 100 | 17 | 693 | ||
| 9 | 102 | 18 | 432 |
About SOMATH & Kid Einsteins
SOMATH — School of Math is a math-focused school on the Upper West Side of Manhattan for students in grades 1–12. The Kid Einsteins program (grades 3–5) drills multiplication and division fluency, fractions and decimals, area and perimeter, ratios, and structured word problems in small groups of 6–8 students. This is Class 4 of the Kid Einsteins arc — the natural sequel to Class 3 (×7, ×8, ×9 with area models).
Classes are taught by cofounder Marcelo Ambrozio (Northwestern-trained, 15+ years teaching math in NYC) and the SOMATH team.
Location: 226 W 79th St, 1st Floor, New York, NY 10024 (Upper West Side)
Phone: (646) 668-6151
Email: hello@schoolofmath.us
Book a free evaluation for your child — we’ll assess where they are and place them in the right small group.