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Regents Geometry June 2026 — Part IV Answer & Full Solution
Free worked solution for the 6-credit Part IV question on the June 2026 New York State Regents Geometry exam. This is the longest question on the test — a coordinate-geometry problem with four sub-parts. This is the final post in our four-post series covering all 35 questions.
📄 Original NYSED exam (PDF)
All diagrams, coordinate grids, and reference sheet are in the official New York State Education Department release. Open it in a second tab so you can see the figure as you work through the question below.
Download the June 2026 Geometry Regents PDFHow Part IV is graded. Part IV is the single hardest question on the test, worth 6 credits. A correct numerical answer with no work receives only 1 credit. Each of the four sub-parts is graded separately, so partial credit is available — do not skip a sub-part just because you are stuck on an earlier one. Use the optional grid on the following page to visualize the points, but every algebraic step must still be written out.
Sections
What Part IV tests
Every recent Geometry Regents ends with a large coordinate-geometry question. The Regents wants to know whether you can move fluently between four core coordinate tools — slope, midpoint, distance, and the equation of a line — and whether you can attach the right theorem to each calculation. This June 2026 question stitches together all three foundational coordinate formulas and then asks you to reach a shape classification (parallelogram) and a triangle classification (isosceles).
The three coordinate formulas you will use
- Slope from (x1, y1) to (x2, y2): m = (y2 − y1) / (x2 − x1).
- Midpoint: M = ((x1 + x2) / 2, (y1 + y2) / 2).
- Distance: d = √((x2 − x1)² + (y2 − y1)²).
Ways to prove a quadrilateral is a parallelogram (coordinate plane)
- Show both pairs of opposite sides are parallel (equal slopes). ← used here.
- Show both pairs of opposite sides are congruent (equal distances).
- Show one pair of opposite sides is both parallel and congruent.
- Show the diagonals bisect each other (equal midpoints).
Isosceles triangle definition
A triangle with at least two congruent sides is isosceles. On the coordinate plane, prove isosceles by computing two side lengths with the distance formula and showing they are equal.
Part IV — Question 35 (6 credits)
Coordinate geometry · four sub-parts · click the card to reveal the full worked solution.
Question 35Triangle ABC has vertices A(−3, −1), B(−5, 2), and C(−1, 8).
(a) State the coordinates of point D such that quadrilateral ABCD is a parallelogram.
(b) Prove ABCD is a parallelogram.
(c) State the coordinates of point E, the midpoint of BC.
(d) Prove ▵ABE is an isosceles triangle.
(b) Prove ABCD is a parallelogram.
(c) State the coordinates of point E, the midpoint of BC.
(d) Prove ▵ABE is an isosceles triangle.
Find the fourth vertex D
Idea. In parallelogram ABCD, the diagonals are AC and BD, and they bisect each other. That means the midpoint of AC equals the midpoint of BD.
Midpoint of AC: ((−3 + (−1))/2, (−1 + 8)/2) = (−4/2, 7/2) = (−2, 3.5).
Set midpoint of BD equal: ((−5 + Dx) / 2, (2 + Dy) / 2) = (−2, 3.5).
Solve each coordinate:
- (−5 + Dx) / 2 = −2 ⇒ −5 + Dx = −4 ⇒ Dx = 1.
- (2 + Dy) / 2 = 3.5 ⇒ 2 + Dy = 7 ⇒ Dy = 5.
D = (1, 5)
Part (b)Prove ABCD is a parallelogram (slopes method)
Method. If both pairs of opposite sides have equal slopes, both pairs are parallel, so ABCD is a parallelogram.
Slope of AB from A(−3, −1) to B(−5, 2):
mAB = (2 − (−1)) / (−5 − (−3)) = 3 / (−2) = −3/2.
Slope of DC from D(1, 5) to C(−1, 8):
mDC = (8 − 5) / (−1 − 1) = 3 / (−2) = −3/2.
mAB = mDC, so AB ∥ DC.
Slope of BC from B(−5, 2) to C(−1, 8):
mBC = (8 − 2) / (−1 − (−5)) = 6 / 4 = 3/2.
Slope of AD from A(−3, −1) to D(1, 5):
mAD = (5 − (−1)) / (1 − (−3)) = 6 / 4 = 3/2.
mBC = mAD, so BC ∥ AD.
Both pairs of opposite sides are parallel, so ABCD is a parallelogram (definition of parallelogram).
Find the midpoint E of BC
E = ((xB + xC) / 2, (yB + yC) / 2) = ((−5 + (−1)) / 2, (2 + 8) / 2) = (−6/2, 10/2).
E = (−3, 5)
Part (d)Prove ▵ABE is isosceles
Method. Compute the three side lengths using the distance formula and show at least two of them are equal.
Length of AB from A(−3, −1) to B(−5, 2):
AB = √((−5 − (−3))² + (2 − (−1))²) = √((−2)² + 3²) = √(4 + 9) = √13.
Length of BE from B(−5, 2) to E(−3, 5):
BE = √((−3 − (−5))² + (5 − 2)²) = √(2² + 3²) = √(4 + 9) = √13.
AB = BE = √13, so ▵ABE has two congruent sides.
∴ ▵ABE is isosceles (a triangle with at least two congruent sides is isosceles). ■
Big ideas to remember on test day
- Attack the sub-parts in any order. If you are stuck on the parallelogram proof, do parts (c) and (d) first — each sub-part is graded separately.
- Diagonals bisect each other is the fastest route to finding a missing parallelogram vertex from three given ones. Midpoint = midpoint.
- Four slopes for a parallelogram, three sides for an isosceles. Match the tool to the goal.
- Show every substitution. The distance formula counts as three lines of work: formula, substituted, simplified. Skip any of the three and you may lose a credit.
- Leave the radical. √13 is exact; do not decimal-approximate unless the problem asks for it.
- Write the concluding sentence. “∴ ABCD is a parallelogram because both pairs of opposite sides are parallel.” “∴ ▵ABE is isosceles because AB = BE.” These sentences are how the grader knows you finished the proof.
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This walkthrough is provided for educational purposes. The June 2026 Geometry Regents exam is publicly released by the New York State Education Department. Questions and figures are the property of NYSED.
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